9k^2-27k=0

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Solution for 9k^2-27k=0 equation: 



9k^2-27k=0

a = 9; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·9·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*9}=\frac{0}{18}
=0
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*9}=\frac{54}{18}
=3
$

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